Whether you want to perform substitution on $line or $name is unclear (it is probably $name though), but the substitution expects the $_ variable to be initialized.

When you use s/// (and many other Perl constructs) in "void context" - w/o arguments, it assumes the $_ var is its argument. The regext in the if() doesn't insert anything into $_, so you get the warning.

It's best to be explicit... supply s/// with the var you want the substitution on, then you won't have to scratch your head for too long trying to understand bugs like this.

In reply to Re: substitution (s///) by spurperl
in thread substitution (s///) by matth

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