For one thing, you are ignoring the first element of the array ( Perl arrays are zero-based ), and comparing phantom elements at the end of the array. For example, if you have this array:
@stuff = ( 90, 5, 4 );
Your code will start with the second element, and compare the last element to a nonexistent ( and therefore undefined ) value ( $stuff[3] ).
For another thing, you are resetting the value of $highest every time a following element has a lower value. With the code as it now exists, $highest will always be the last element in the array. I urge you to work this out by hand with the short example.
Here is something that does what you want:
my $highest = 0; foreach my $element ( @numbers ) { $highest = $element if $element > $highest; } print $highest;

In reply to Re: finding highest number by FamousLongAgo
in thread finding highest number by Anonymous Monk

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