I think this does what you mean, assuming you want to find the longest subset of increasing integers: 

my @a = (1,2,4,8,4,5,6,7,8); # sample data
my ($current, $previous);
my $tmp_max = 1;
my $max = 1;

while (@a) {
  $previous = shift(@a) ;
  $current = $a[0] or last;
  if ($previous + 1 == $current) { # or $previous < $current if number
+s may increase by more than 1
    $tmp_max++;
  } else {
    $tmp_max = 1;
  }
  $max = $tmp_max if ($tmp_max > $max);

}
print "$max\n";

[download]

Given the sample data, prints "5", for 4-8.

Update: alas, I seem to have answered the wrong question {chagrin}.

In reply to Re: Items in Order by djantzen
in thread Items in Order by artist

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