I couldn't decipher what you are using "Ordered Array: (1,2,3,8,4,5,6)" for. But, finding all subsets from (2,1,4,3,5) of length 3 where the members appear in order, you can use:
sub genOrderedSubList {
my $size= shift @_;
my @list= @_;
my @idx= ( -1 );
return sub {
my $i= $#idx;
while( 1 ) {
do {
++$idx[$i];
if( $#list < $idx[$i] ) {
if( --$i < 0 ) {
@idx= ( -1 );
return;
}
redo;
}
} while( 0 < $i
&& $list[$idx[$i]] <= $list[$idx[$i-1]] );
return @list[@idx] if $i == $size-1;
$idx[$i+1]= $idx[$i];
++$i;
}
}
}
@ARGV= ( 3, 2,1,4,3,5 ) if ! @ARGV;
my $gen= genOrderedSubList( @ARGV );
my @res;
while( @res= $gen->() ) {
print "@res\n";
}
-
tye
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