Thanks for the link, now I got my answer. However, now a more serious question is raised.

According to perldata, the denominator of that fraction is the number of units of momery, perl has allocated for your hash, and more interestingly, the denominator is always a number of 2's power.

This algorithm of allocating memory really worries me, because it indicates, that it intends to waste more memory, when your hash gets bigger, because whenever you used up the memory been already allocated, perl would just double it.

I can understand the thought behind this algorithm, one is thinking, okay, I already gave you a big piece of memory, but it is still not big enough for you, instead of wasting time to give you all those small pieces, let's just double the memory I gave you.

I can understand this is a space vs. time thing, and I have no problem with that, but I still feel this algorithm is way too rough. there must be other more delicate/fine solutions.

In reply to Re: Re: what does that value mean, when you evaluate hash in a scalar context? by pg
in thread what does that value mean, when you evaluate hash in a scalar context? by pg

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