I am obviously not welcomed :-) Your first line did give you a syntax error, didn't it? Other problems, which the compiler will not tell you, are the following:
  1. The quots surrounding $MemberCall and $i are not neccessary, although they do not cause problem in your case.
  2. if you set $found to "1", then you can not use == later, == is for numbers.
@AllowedRanks = ("Recruit","General","Captian","Civilian","Airman"); $found=0; my $MemberCall = "me"; foreach $i (@AllowedRanks){ if($MemberCall eq $i){ $found=1; } } if($found==1){ &Welcome; }else{ &NotWelcome; } sub Welcome { print "welcome\n"; } sub NotWelcome { print "Notwelcome\n"; }

In reply to Re: Looking Through Arrays? by pg
in thread Looking Through Arrays? by ACJavascript

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