No, this code will loop infinitely on many inputs, e.g.
my @range3 = ([0, 10], [5, 20]); To fix that, you need
redo if $j < @range;
But it is also buggy for contained intervals. The input my @range4 = ([0, 20], [5, 8]); will give the output interval ([0, 8]). Here is the complete correct code:
for (my $i = 0; $i < @range; $i++) {
my $e = $range[$i][1];
for(my $j = $i+1; $j < @range; $j++) {
unless($range[$j][0] > $e) {
if ($range[$j][1] > $e) {
$e = $range[$i][1] = $range[$j][1];
}
splice @range, $j, 1;
redo if $j < @range;
}
}
}
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