print (ref $result) ? (join ":", @$result) : "no results";

"I looks like a function, hence it is a function." That will parse as   (print(ref $result)) ? (join ":", @$result) : "no results"; You need to disambiguate with a +:   print +(ref $result) ? (join ":", @$result) : "no results"; But I don't understand what's wrong with   print ref($result) ? (join ":", @$result) : "no results"; or for that matter,   print ref $result ? (join ":", @$result) : "no results"; either. Since that will actually parse the intended way.

ihb

In reply to Re: Re: using join with a print ref statement by ihb
in thread using join with a print ref statement by Bismark

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