Your initial question is not using a placeholder for the table name -- you are attempting to interpolate a variable to get the table name into a string which is then passed to the prepare routine. This is not working as you expect because you are using single quotes ( as stated by the previous posters ).

Make your line look like this instead and it should work: 

$sth = $db->prepare("SELECT Names FROM $table WHERE Name = ?");

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In reply to Re: Re: Variable table by Sifmole
in thread Failure plugging table into into query by Raziel

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