Hi, I'm writing a program that uses a hash of hashes. At one point this program checks to see if a hash exists within a hash. Much to my suprise, checking for its existence caused that key to come into existence. Below is some sample code that illustrates what I'm talking about: 

#!/usr/bin/perl -w

use strict;
use warnings;

my %foo;

if(exists($foo{qux})) {
    print "\$foo{qux} exists";
}

if(exists($foo{bar}{baz})) {
    print "\$foo{bar}{baz} exists\n";
}

if(exists($foo{bar})) {
    print "\$foo{bar} popped into existence\n";
}

if(exists($foo{qux})) {
    print "\$foo{qux} popped into existence\n";
}

[download]

And it outputs: $foo{bar} popped into existence.

This is very confusing to me because I never did anything with $foo{bar} except check to see if it contained a reference to a hash (which I though was supposed to prevent autovivification).

My two questions are why does this happen (and why only with a hash of hashes) and how can I test for a hash within a hash without causing the key in question to come into existence?

Thanks!

In reply to Autovivification with hash of hashes by Mr_Person

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