You are very close. Try making the regex look like this:
split(/(?<=\S)(?=\s)/);
That is, use
both look-behind and look-ahead
assertions, both zero-width. (update: made the above line
coincide with the tested code below) I tried the following snippet
on the command line to verify that:
$s="AAA B X Y Z W\n";
@a=split(/(?<=\S)(?=\s)/, $s);
print length($s),":$s";
print join(":",length(join("",@a)),scalar(@a),"\n");
print join("\n",@a),"\n";
Output:
20:AAA B X Y Z W
20:7:
AAA
B
X
Y
Z
W
Note that this treats the final LF (or CRLF, if that's your
flavor) as a token -- the second line of output shows that
the array got seven elements, while the string had just six
non-whitespace tokens followed by LF.
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