I've got this snippet (part of a large script that runs with strict & -w!) and wondered if there was an easier way of getting the number of keys in the hash that satisfy a condition (or two) than looping through the hash and checking each element as I do below. 

for $clipnum(0 .. $noofclips-1)
{     
    if ($file{$clipnum}{FILETYPE} eq "Menu")
    {  
        $menucount++;
        
        if ($file{$clipnum}{VOICEOVER} eq "No")
        { $menunvocount++; }
        else
        { $menuvocount++; }
    }  
      
    if ($file{$clipnum}{FILETYPE} eq "Video")
    {            
        $videocount++;                
      
        if ($file{$clipnum}{VOICEOVER} eq "No")
        { $nvocount++;    }             
        else
        { $vocount++; }             
    }  
}

[download]
Can you do something like the below in one line instead?

$menucount = (all keys in hash that equal) ($file{$clipnum}{FILETYPE} 
+eq "Menu" && ($file{$clipnum}{VOICEOVER} eq "No")

[download]

I know how to find the total number of keys in a hash - $num_keys = scalar keys %file; but not how to make it do that if & only if certain conditions are met.

thanks for your help in advance

dmtelf

In reply to Keeping a count of matches in a hash that satisfy more than 1 condition by dmtelf

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