If you stick the count variables in a hash you can reduce the loop code a bit. Not sure if this is any faster or more efficient. You have to define the count structure up front as well. 
my $count =
{
        "Menu" => {
                        "Count" => 0,
                        "Voice" => 0,
                        "NoVoice" => 0},
        "Video" => {
                        "Count" => 0,
                        "Voice" => 0,
                        "NoVoice" => 0}
};

foreach my $entry (values(%$file))
{
        $count->{$entry->{FILETYPE}}->{"Count"}++;

        if($entry->{VOICEOVER} eq "No")
                { $count->{$entry->{FILETYPE}}->{"NoVoice"}++ }
        else
                { $count->{$entry->{FILETYPE}}->{"Voice"}++ }
}

# Example getting one of the counts out.

print $count->{"Menu"}->{"Count"} . "\n";

[download]
When I started this I thought it would come out smaller than this. Thought someone might find it useful or make it a bit smaller.

In reply to Re: Keeping a count of matches in a hash that satisfy more than 1 condition by barndoor
in thread Keeping a count of matches in a hash that satisfy more than 1 condition by dmtelf

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