There is a very weird thing happening when I’m using the last; statement. I'm comparing two arrays to find if any elements are missing off one. The strange thing that is happening is when I go to break out of a while loop with the last; statement the loop claims 2 elements are missing. When I use the next statement the loop can find every element. I know for a fact every element is there. The arrays are the same in both test cases. Here is a snippet of code. Can anyone explain to me why this is happening and how to fix it. 
#Here are a few elements of the hash
%prolist = (

'1', 'CMD',
'2', '/bin/sh',
'3', 'rds',
'4', 'SysExec',
'5', '/oasis/bin/sysmenu',
'6', '/oasis/bin/TS_TextSrvcs',
}

foreach $val(sort keys(%prolist)){

        while(<@list>){
            if ("$prolist{$val}" eq "$_" ){
                $set = 1;
                last; }
                            }
        
    if ($set == 0){print "NF: $prolist{$val}\n"; }
    $set = 0;
}

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Its always the same 2 elements too. #2 and #3

In reply to loop control by maxl90

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