I'll admit ignorance of overloading but wouldn't only apply if you went $obj_var_a == $obj_var_b? The snippet I showed took references to both and compared the address on the references. Wouldn't that bypass any == overloading because the newly created references aren't overloaded?

Seeking Green geeks in Minnesota

In reply to Re^5: my least favorite perl feature by diotalevi
in thread my least favorite perl feature by waxmop

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