$# applies only to print itself doing the conversion. Interpolating the variable into a string doesn't bring it into play.
Exactly! Which is why this line works:
print "\n","  $amount   ","-", $taxes," = ", $amount-$taxes;

Also note that $# is deprecated...
Which JamesNC would have known if he had enabled warnings.

... and it's better to explicitly run through sprintf than depend on it.
Is there a way to tell sprintf to add a dollar sign? Or do you have to explicitly append it? Like:
my $net = '$'.sprintf("%.2f", $amount - $taxes);

In reply to Re: Re: Odd behavior of $# by Mr. Muskrat
in thread Odd behavior of $# by JamesNC

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