Ok, if you want @array to have ONE element, which is an array reference to a list of references to scalars, then: 
@array = [ \($a,$b,$c) ];

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is for you. But maybe you meant: 
@array = \($a,$b,$c);

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Regardless, here is something to watch out for: 
@array = (1..10);
print scalar @array;  # 10

$a = \@array;
print $a;  # ARRAY(0x12345)

$b = \(@array);
print $b;  # SCALAR(0xabcde)
# is a ref to the last element of @array)

@c = \($a,@array);
print @c;  # SCALAR(0x13579)ARRAY(0x12345)

@d = \($a,(@array));
print @d;  # SCALAR(0x13579)SCALAR(0x11111)SCALAR(0x11112)...

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I hope you see the trend. \(LIST) returns a list of references to the EXPLICIT elements of the list. \(THIS,(THAT),THOSE) returns a reference to THIS, expands THAT into a list and then takes references to each element of the list, and then a reference to THOSE. It can be icky. </code> $_="goto+F.print+chop;\n=yhpaj";F1:eval

In reply to Re: reference nastiness by japhy
in thread \($a, $b, $c) eq (\$a, \$b, \$c), is \$a, $b, $c eq \$a, \$b, \$c? by Anonymous Monk

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