i saw something like this here on PM before...

#!/usr/bin/perl
use strict;
use warnings;

my $points = shift @ARGV;

# @player = ( [ value, rank, name ], ... )
# likely to sort by value,rank or rank,value

my @player = map {
    chomp;
    [ (split ':', $_)[2,1,0] ]
    } <DATA>;

sub print_player { sprintf "%s(%s)[%d]$/", @{$_[0]}[2,1,0]; }

# the sort determines the order you try to get the most of,
# i'm going for more guys with big values.

@player = sort {$b->[0] <=> $a->[0]} @player;

my $pointbuff = 'x' x $points;
my $re = join '', map("((?:x{$_->[0]})*)", @player), '(x*)';
my @counts = $pointbuff =~ /$re/;

# so fooguy(a)[4] and barguy(b)[3] would give
# '((?:x{4})*)((?:x{3})*)(x*)'
# the final capture being what's left over.
#
# with points = 11
# pointbuff = xxxxxxxxxxx
# which maches xxxx twice and then xxx once with none left over.

my @match = map {[ $_, shift @counts ]} @player;

print "$points points will get you:$/";

foreach my $match (@match) {
    printf "%d %s",
      length($match->[1]) / $match->[0][0],
      print_player($match->[0]);
}

printf "with %d left over.$/", length $counts[0];


__DATA__
blastaar:v:138
mr fixit:u:104
daredevil:r:30
blob:v:51
boomerang:e:34
wolverine:e:61
skrull commando:v:18

[download]

i don't remeber if there's a way to make it cycle through all possible matches or not.

./game.pl 4096
4096 points will get you:
29 blastaar(v)[138]
0 mr fixit(u)[104]
1 wolverine(e)[61]
0 blob(v)[51]
0 boomerang(e)[34]
1 daredevil(r)[30]
0 skrull commando(v)[18]
with 3 left over.

[download]

In reply to Re: army building by zengargoyle
in thread army building by dshahin

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