Howdy!

I can't tell if my posited circumstance is in place.

Whether I say $request->new or ref($request)->new has no effect on the assumption that the ref($request) is of the appropriate class (either directly or by inheritance). If it is important to verify the particular package that a ref is blessed into to ensure that the ->new part goes to the right place, then you need to check that explicitly. I don't see where that bears on the particular dispute at hand.

The sample code presented would lead me to the presumption that the range of values ref($request) could take would all have the expected methods available to it. The code would die if that assumption were invalid. If I were faced with that range of classes for $request, I would have to dredge through the various packages to discern what variations in behavior were occurring to figure out just where to patch finish().

I did note that I assumed that the packages were documented to permit users to know what methods were provided where. I'm still not seeing the objection.

yours,
Michael

In reply to Re: (Re:)+ $class = ref $class || $class by herveus
in thread Constructor/Factory Orthodoxy by mojotoad

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