$regex = '(\w+)|(\d+)|(\s+)|([^\w\d\s]+)'; $text = 'The world is foo 2!'; while ( $text=~s/^$regex// ) { print '\w+',$/ if $1; print '\d+',$/ if $2; print '\s+',$/ if $3; print '[^\w\d\s]+',$/ if $4; }
$regex = '(\w+)|(\d+)|(\s+)|([^\w\d\s]+)'; $text = 'The world is foo 2!'; while ( $text=~s/^$regex// ) { print '\w+',$/ if defined $1; print '\d+',$/ if defined $2; print '\s+',$/ if defined $3; print '[^\w\d\s]+',$/ if defined $4; }
You could do something like the above, where $1 .. $4 deal represent which set of parens matched. Note that I changed the .*? to [^\w\d\s]+, as I assumed this is what you meant, as .*? will try to match nothing first (which it will always do and replace it with nothing (as per s/// operation). So your code was probably looping forever.

Also the $1 was not printing as there were no capturing parens in your regular expression.

update: striked out old code, and updated it as per Abigail-II's suggestion below.

-enlil


In reply to Re: Determing what part of a regex matched. by Enlil
in thread Determing what part of a regex matched. by Anonymous Monk

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