I have no idea what you mean. All this regex does is walk the string (char by char) with a 1 char buffer (the last char). When it gets a match (last char not \\ and char eq ') it gets a match and we record the position. This is hardly a regex at all!

Here it is completely C-ified - no regexes in sight. Possibly faster than the original post to boot but I can't be bothered to test. 

$str  = "  '==\\'==' '==5=='  '\\'\\'' '\\'3' '\\'' '1'  '' ";

my $pos = 0;
my $len = length $str;
my $last = '';
my $char;
while ( $pos < $len ) {
   $char = substr $str, $pos, 1;
   push @pos, $pos if $char eq "'" and $last ne "\\";
   $pos++;
   $last = $char;
}

for ( my $i= 0; $i <@pos; $i +=2 ) {
    my $begin = $pos[$i]+1;
    my $end   = $pos[$i+1];
    my $str   = substr $str, $begin, ($end -$begin);
    print "$begin $end |$str|\n";
}

[download]

cheers

tachyon

s&&rsenoyhcatreve&&&s&n.+t&"$'$`$\"$\&"&ee&&y&srve&&d&&print

In reply to Re: Re: Re: regexp causes segfault by tachyon
in thread regexp causes segfault by Anonymous Monk

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