I am using hash reference to pass between function. Although I use delete, assing to void =(), and try all of them in the function in which I receive the reference the memory does seem to get freed up. Is there some way of explicity telling the interpreter to forcibly free what is really free?

Or does the hash reference needs to freed in a different way?

sample code snapshot:

sub f2 {
  my $ht_ref = shift;
  my %ht = %$ht_ref;
  print "some val = ", $ht{1}, "\n";
  %ht=();
  undef %ht;
}
sub f1 {
  my %ht=();
  my $i;
  for ($i=0; $i<0xfffff; $i++) {
    $ht{$i} = $i;
  }
  f2 (\%ht);
  %ht=();
  undef %ht;
}

f1();
while (1) {
  # sleep here and monitor the memory.  memory
  # does'nt seem to come down :((
  sleep (5);
}

[download]
thanks,
-sureshr

In reply to Memory leak when using hash 'references' by sureshr

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