Actually, the way you are doing it, you are comparing arrays. Therefore you may find useful this node:

comparing arrays

The best method there was MeowChow's at (MeowChow) Re2: (Efficiently) comparing arrays

To take advantage of hashes capabilities, though, I would rather use something like

#!/usr/bin/perl -w use strict; my %first = ( aa => 1, bb => 2, cc => 3, ee => 6); my %second = ( bb=> 2, cc => 3, dd => 4 ); sub compare_one_hash_keys { my ($h1, $h2) = @_; return grep ( {not exists $h2->{$_} } keys %$h1) } sub compare_both_hash_keys { my ($h1, $h2) = @_; return grep ( {not exists $h2->{$_} } keys %$h1), grep ( {not exists $h1->{$_} } keys %$h2) ; } print compare_one_hash_keys( \%first, \%second), "\n"; print compare_one_hash_keys( \%second, \%first), "\n"; print compare_both_hash_keys( \%first, \%second), "\n"; __END__ prints: aaee dd aaeedd

The first sub returns an array of keys present in one hash and missing in the other one. The second one combines the differences in both hashes. I think you may use this method to implement what is closer to your needs.

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In reply to Re: Comparing all keys in a hash by gmax
in thread Comparing all keys in a hash by rinceWind

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