UPDATE
Much faster way in the node below .
If your hashes aren't too large on average I wonder if something like this would be efficient. 
sub compare_keys {
   my ($h1,$h2);
   my ($k1,$k2) = ( join('',sort keys %$h1), join('',sort keys %$h2) )
+;
   return $k1 eq $k2 ? 1 : 0;
}

[download]
Of course I know you're not suppose to rely on hash order but would two hashes with the same keys return in the same order? I would think so but don't know (And don't have time to test) but if it did you could skip the sort. But it probably would be a bad idea.

-Lee

"To be civilized is to deny one's nature."
UPDATE
Fixed typo UPDATE
Fixed typo, thanks Helter

In reply to Re: Comparing all keys in a hash by shotgunefx
in thread Comparing all keys in a hash by rinceWind

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