The perlfunc manpage says about the keys function:
As an lvalue keys allows you to increase the number
of hash buckets allocated for the given hash. This can gain
you a measure of efficiency if you know the hash is going
to get big.
I decided to try benchmarking it to see how much it did
increase efficiency and ran this code:
use Benchmark;
timethese( 100, {with => q{
my %hash;
keys( %hash ) = keys( %hash ) = 10000;
foreach $i (1 .. 10000) {
$hash{"key$i"} = $i;
}
},
without => q{
my %hash;
foreach $i (1 .. 10000) {
$hash{"key$i"} = $i;
}
},
});
My results from this show that using keys didn't acually
increase efficiency at all...
Benchmark: timing 100 iterations of with, without...
with: 14 wallclock secs (13.73 usr + 0.04 sys = 13.77 CPU) @ 7
+.26/s (n=100)
without: 14 wallclock secs (13.86 usr + 0.00 sys = 13.86 CPU) @ 7
+.22/s (n=100)
I would think that since this would make it so the hash
wouldn't constantly have to be expanded this would greatly
increase efficiency. Printing out the number of buckets
filled and total number of buckets shows that without
allocating the keys beforehand, the hash is reallocated
somehow when expanded whereas it isn't when you do allocate:
1/16384
2/16384
3/16384
4/16384
5/16384
6/16384
7/16384
8/16384
9/16384
10/16384
vs.
4/8
5/8
6/8
7/8
7/8
7/8
7/8
7/8
12/16
13/16
13/16
13/16
etc...
Am I doing something wrong in my
benchmark? Or is there some magic going on behind the scenes
of hashes that make expanding the hash not an issue?
Thanks
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