I'm not at all sure about using _ as the delimiter, but everything else I tried was altogether too messy.
Just so you know, they curlies dont need to be escaped here. And this in turn means the traditional regex delimiter looks fine
s/{.*?}/{$sub[$n++]}/g;
As the open curlie starts at the BOS it _can't_ have its meta meaning, and thus needs no escape. Dont worry, as I found out ages ago, perl is quite smart about delimiters in regexes. For instance
s{{.*?}}{{$sub[$n++]}}g;
also works just fine, even if it looks a mess.
Anyway, just my $0.02
---
demerphq
<Elian> And I do take a kind of perverse pleasure in having an OO assembly language...
In reply to Re: Re: Re: Re: looking for a regex
by demerphq
in thread looking for a regex
by Anonymous Monk
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