I don't think it does count as brute force.
davorg may
disagree, of course, but here are my two cents.
This is brute force:
(Note: this is deliberately not perl-idiom, just to be obtuse...)
my @Unique;
for (my $i = 0; $i != @Arr; $i++){
my $Val = $Arr[$i];
my $Found = 0;
for (my $j = 0; $j != @Unique; $j++){
if ($Val == $Unique[$j]){
$Found = 1;
last;
}
}
if (not $Found){
push @Unique, $Val;
}
}
print 'Unique values are: ', join ', ', @Unique;
Now, in perl idiom, we do all that in one line using a hash.
Of course, the specific problem we are solving here would
be much simpler, even in 'C' mentality...
I guess my definition of brute-force is "the opposite of
perl idiom."
Russ
Brainbench 'Most Valuable Professional' for Perl
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