Something like this perhaps:

#!/usr/local/bin/perl use strict; use warnings; my %conv = (k => 1000, kb => 1024, g => 1000000, gb => 1024 * 1024); # Note that the keys are sorted to put the longer # matches first in the regex my $keys = join '|', sort { length $b <=> length $a } keys %conv; while (<DATA>) { print "$_ -> "; s/(\d+)($keys)/$1 * $conv{$2}/e; print "$_\n"; } __END__ 30k 30kb 10g 10gb

This gives:

$ ./test.pl 30k -> 30000 30kb -> 30720 10g -> 10000000 10gb -> 10485760

Update: Yes I know that some of the multipliers are wrong. Correcting them is left as as exercise for the reader :)

--
<http://www.dave.org.uk>

"The first rule of Perl club is you do not talk about Perl club."
-- Chip Salzenberg


In reply to Re: converting "30k" string to integer by davorg
in thread converting "30k" string to integer by dwhite20899

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