is @a4=qw(b g g); considered a subset? If so how about this solution?
@a1=qw(a b c d e f g);
@a2=qw(b g);
@a3=qw(e f g h);
print "a1, a2 => ",subset(\@a1, \@a2),"\n";
print "a1, a3 => ",subset(\@a1, \@a3),"\n";
sub subset {
my($a1, $a2)= @_;
my(%subset);
@subset{@$a2}=@$a2;
delete @subset{@$a1};
return scalar(keys %subset)==0;
}
It first defines hashkeys for all elements from @a2, then removes all haskeys from @a1. If any haskey remains, @a2 had elements not present in @a1.
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