hi all
I am doing a task to ftp to a server and pick up a file which is one day older than the current date
I am using the perl Net:FTP module

files are in the format yearmonthday.dat e.g. 20030601.dat (Ist of june) 
my @current = `date`;
($dnr,$month,$date,$tnr,$rr,$year)= split(/\s+/,$current[0]);
chomp $year;chomp $date;chomp $month;
$date-=1;

my %month_conv=("Jan"=>"01","Feb"=>"02","Mar"=>"03","Apr"=>"04","May"=
+>"05","Jun"=>"06","Jul"=>"07","Aug"
=>"08","Sep"=>"09","Oct"=>"10","Nov"=>"11","Dec"=>"12",);

$pingmonth=$month_conv{$month};
$filename="$year$pingmonth$date.dat";
print "getting $filename\n";


$dir='/log_recv/telecom/DATA';
use Net::FTP;

        $ftp = Net::FTP->new("aaa.com")|| die("Could not connect: $@\n
+");
        $ftp->login("xxx","yyy")||die("Wrong username or password ");
        $ftp->binary();
        $ftp->cwd("$dir")||die("Could not change path ");
        #@aa=$ftp->ls("$dir");
        $ftp->get("$filename")|| die("File not found $filename\n");
        $ftp->quit;

[download]

i would like to know the best method for handling end of the month conditions. e.g. on the 1st of june my script would fail
I had thought of
run ls -t take the output in an array and pick up arr1(second field as we need a one day older file)<how is this done using Net:FTP
convert to epoch seconds minus 86400 convert back and get .
anyideas on a efficient and reliable way
thanks

In reply to FTP and get file date manipulation problem by chimni

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