Ack. Damn those non-scalar contexts!
perl -e 'print $#a, "\n", @a, "\n", $#a+1, "\n"'
-1
0
Thus clearly showing that @a is undef.
Which is true. In a list context...
If I'd remembered to include scalar around it:
perl -e 'print $#a, "\n", scalar (@a), "\n", $#a+1, "\n"'
-1
0
0
, I'd have got the right answer...
My bad.
--
Tommy
Too stupid to live.
Too stubborn to die.
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