Hi Monks,

inspired by strats little 'regards-obscu' i played a little with the comma-operator.

I found this strange behavior

# perl -e 'print "one\n",print "two\n"'
two
one
1

[download]
Okay, i'm thinking the '1' represents the successful processing of the second print which will be printed after the 'one'. The printing of 'two' at first seems to be dealing with the fact that the lefts of comma-separated values are thrown away and only the rightmost is returned.

When i tried another example i became really confused.

# perl -we 'print $a=3,"\n",print $a-5,"\n"'
-2
3
1

[download]
Why does the second print already know the value of $a, if the working direction is reverse ?

In reply to comma-operator quirks by tos

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