basically all i need is a regex that will either accept a $ # % >  ~ with lots of other random stuff before it and one that will accept \[\e[0m\] [0m also with random things before it. each of these two possible matchs may allow \s to be after it.

and due to the restrictions of the rest of the program it must be in one single regex, not two seperate checks.... thus both of those checks need to be in the same expression..... sigh

thanks for the help

In reply to a really simple regex that for some reason I cannot solve by Anonymous Monk

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