You're not arranging for your child processes to exit; so they takeup where the parent left off.
The first time through the foreach loop, you fork an new process. When that process finishes &VF4($line);, it loops around and passes throguh the fork, doing another fork to run &VF4($line); - which the parent process also did. Hence &VF4($line); runs twice for $fiveprimedir
I think if you exit; after &VF4($line); you get the effect you want. (UNTESTED).
update: missed the second half of your question, about the main process finishing immediately after the forks.
use of fork is:
# UNTESTED
for $line (@whatever)
{
$pid = fork(); # 0 in child, child's pid in parent
if ($pid)
{
# in parent process
push @pids, $pid;
}
else
{
#child processe
&VF4($line);
exit;
}
}
for ( @pids ) { waitpid($_,0) }
# wait for all children
--Bob Niederman, http://bob-n.com
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