I've read over variable variables and didn't get an answer to my question. Essentially, in my code, I must create a few arrays, each with different names. The names are determined earlier in the script, and a picked from a list which is never influenced by user input. The code I have: 
my $tablename =$$tables[$x];
my @{$tablename};

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@tables is the list of names and $x is a variable used in a for loop. I get the error that I cannot use an undefined value as an array reference on this line, yet $tablename is most definitely defined. It works after saying "no strict 'refs';" but I'm wondering if there is a way to accomplish this without soft refs. Thanks for your input.

In reply to Create an array with another variable by lpoht

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