It looks like what you need to do is: get the last value you had, multiply it by 31, and add the next number; repeat. In Perl that would become:
sub hashing {
my $s = shift;
my $acc = 0;
foreach my $c (unpack 'C*', $s) {
$acc *= 31;
$acc += $c;
}
return $acc;
}
You will have overflow problems, I think. Likely you should only retain the $n (<=32?) lower bits of $acc. Your remark on "using int arithmetic" also points in that direction. So I'll modify that into:
sub hashing {
my $s = shift;
my $acc = 0;
foreach my $c (unpack 'C*', $s) {
$acc *= 31;
$acc += $c;
$acc %= 0x100000000;
}
return $acc;
}
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