I want an extra layer of indirection between me and @ISA, because I don't like assuming that @ISA was already empty when I said our @ISA = qw(Foo);. use base provides that layer and gives you a little extra stuff.

----
I wanted to explore how Perl's closures can be manipulated, and ended up creating an object system by accident.
-- Schemer

Note: All code is untested, unless otherwise stated

In reply to Re: •Re: Avoiding the Use of @ISA = qw(Foo::Bar); by hardburn
in thread Avoiding the Use of @ISA = qw(Foo::Bar); by hardburn

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