Having puttered, I share:
#!/usr/bin/perl -w
use strict;
use English;
use vars qw($boo);
$a = foo() if 0;
sub bar {}
END {
no strict 'refs';
my $table = '::';
SYMBOL:
for my $sym (sort {lc($a) cmp lc($b)} keys %{$table}) {
next if $sym =~ /::$/ or $sym =~ /^[A-Z0-9]/;
my $name = $table . $sym;
next if $name =~ /^::\W/;
foreach my $thing qw(ARRAY HASH IO) {
if (defined *{$name}{$thing}) {
next SYMBOL;
}
}
print "Look at this!\n";
unless (defined *{$name}{CODE}) {
warn "Possible undefined routine '$sym'";
}
}
}
The problem is that
*{$name}{CODE} is as expected,
undef for symbol
foo, and not
undef for symbol
bar, but it is also
undef for symbol
boo.
That is, there's no way to distinguish at the symbol table level between an undefined subprogram name, and a scalar, because both will have
defined(*foo{SCALAR}) && !defined(*foo{CODE})
Hmph.
| -- |
| Jeff Boes |
| Database Engineer |
| Nexcerpt, Inc. |
|
|
|
...Nexcerpt...Connecting People With Expertise
|
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