You seem to be confused about the difference between command-line arguments and piping. If you say
ls *.txt | ./myscript.pl, the STDOUT output of
ls is going to STDIN of your script. Yet you are trying to get the names of those .txt files from
@ARGV.
To actually get the filenames from the piped input, do something like:
chomp( my @filenames = <STDIN> );
for (@filenames) {
... # open, read, etc
}
A better solution for your particular example, though, is
Zaxo's advice above. Use the
-n option, or use the magic
while (<>) loop: both automatically use the members of
@ARGV as filenames and open them in sequence for you, reducing the code you've written to a one-liner.
Alternately, look at xargs to do something like this:
$ ls *.txt | xargs ./myscript.pl
.. which takes the name of each txt file (as given by
ls) and passes it as a command-line argument (i.e, an element of
@ARGV) to myscript.pl (plus or minus quoting/escaping issues)
blokhead
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