and form reading the docs, if methods are prototyped properly ($$), then they're invoked as object methods.
Nope! Prototypes and method-calling are orthogonal. The caller can call any sub as a method, and if a sub is called as a method, the prototype is ignored. You should probably get rid of the prototypes unless you have another reason.

I recommend giving perlobj a good read to understand method calls a bit better. The following two calls are equivalent: 

  My::Greeting->handler($r);  ## class method
  My::Greeting::handler('My::Greeting', $r);  ## equivalent

[download]
So when your handler sub is called as a method, and puts its first argument into $class, it contains the name of the class (a simple scalar). This makes things a little simpler for doing inheritance and subclassing. And that's why Data::Dumper is printing the name of the class -- perhaps you wanted to Dumper($r) instead? Or call handler as an object method ($obj->handler(...)) instead of a class method?

blokhead

In reply to Re: mod_perl and objects by blokhead
in thread mod_perl and objects by geektron

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