If you will only look up one value against the list, or if the list will vary between lookups, then the linear search will be the best solution.
But if your list remains static, and you need to compare more than one value against it, it wouldn't take many linear searches before the cost of sorting the static list and performing a binary chop to locate the nearest two values and then determining the minimum offset between the two would be amortised and begin to pay dividends.
If you need code for this, speak up:)
Examine what is said, not who speaks.
"Efficiency is intelligent laziness." -David Dunham
"When I'm working on a problem, I never think about beauty. I think only how to solve the problem. But when I have finished, if the solution is not beautiful, I know it is wrong." -Richard Buckminster Fuller
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