$foo[1] returns you a scalar and @foo[1] returns you a one element list.

If you do it in a context which is sensible to being in scalar or list context, it might bite you, hence the message given by warnings.

CountZero

"If you have four groups working on a compiler, you'll get a 4-pass compiler." - Conway's Law

In reply to Re: @array[1] is valid?? by CountZero
in thread @array[1] is valid?? by jdklueber

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