Or you could directly get the group info, which is probably what you were looking for (rather than just the id), by joining the tables: 
SELECT group_foo, group_bar
FROM groups, belongs_in
WHERE belongs_in.user_id = ? AND belongs_in.group_id = groups.group_id

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Makeshifts last the longest.

In reply to Re^2: MySQL / Perl theory & design conundrum by Aristotle
in thread [untitled node, ID 280779] by Samn

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