This code:
#! /usr/local/bin/perl
use diagnostics ;
use warnings ;
use strict ;
my $roll = 6 ;
until ($roll == 0) {
chomp $roll ;
$roll -- ;
my $d61 = int(rand(5) + 2) ;
my $d62 = int(rand(5) + 2) ;
my $d63 = int(rand(5) + 2) ;
my $d64 = int(rand(5) + 2) ;
my @d1s = sort { $b <=> $a } $d61 ;
my @d2s = sort { $b <=> $a } $d62 ;
my @d3s = sort { $b <=> $a } $d63 ;
my @d4s = sort { $b <=> $a } $d64 ;
my @all = sort { $b <=> $a } @d1s, @d2s, @d3s, @d4s ;
print "\n@all \n\n" ;
}
produces:
4 4 3 2
6 6 2 2
6 6 5 2
5 3 3 2
5 4 4 3
6 4 3 2
Which is great; but for the next step I need to remove the lowest number (and ultimately add together the remaining three) but I can't seem to ask the correct question of perldocs to get to my answer on hw to remove the lowest number.
Anyone got a way to shove me in the right direction?
--
ellem@optonline.net
There's more than one way to do it, but only some of them actually work.
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