Hi all.

Abigail++ (very cool).

Background:

& = bitwise 'and'
| = bitwise 'or'
^ = bitwise 'xor'

The bitwise xor operator only returns '1' when *one* of the operands is different (e.g. 0 ^ 1, 1 ^ 0). If both operands are the same, the result is '0'.

In ACSII, in order to quickly move from uppercase to lowercase (or vice versa), simply add / subtract 32 from the number respectively. The 'space' character, incidentally, has an ASCII value of 32.

Example:
A = 65
a = 97 (65+32 = 97) and (97-32=65).

Hope this helps, Anonymous Monk.
-Katie

In reply to Re: bitwise string operator question by DigitalKitty
in thread bitwise string operator question by Anonymous Monk

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