That doesn't explain it. \('foo', 'bar', 'baz') is the same as (\'foo', \'bar', \'baz'). Taking a reference to an array certainly doesn't behave that way.

Makeshifts last the longest.

In reply to Re^3: Perl Idioms Explained - ${\$obj->method} and @{[sort @list]} by Aristotle
in thread Perl Idioms Explained - ${\$obj->method} and @{[sort @list]} by broquaint

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