@su = an array of output data in the following format (one line = 1 array element)

(there are spaces at the beginning of the lien as well) 
|-aterm(2559,ddicks)---screen(2560)---screen(2561)---bash(2563)---su(1
+4303,root)---bash(14306)

[download]
i have the following code. 
foreach (@su_procs) {
    print "\n$_\n";
    $user eq split /.*\(/;
    print "$user\n";
}

[download]
all i am getting as $user is the number "2". what am i doing wrong? in the end i am going to want to get the first number and user and the number after su(

In reply to learning: why doesn't this split work? by Hayl_

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