Excellent! Okay, but, why does it work? Does that mean that for (my $i;;) gives my a ref to a lexical variable instead of the actual variable? Hm, or a ref to a copy of whatever is in the init part? That doesn't seem to be it, because moving my $i before the for (;;) doesn't fix it, either.

Can anybody explain the scoping differences between these lines: 

for my $i (1) { print $i }

for ( my $i = 1; $i; $i--) { print $i }

for ( my $i = 1; $i; $i--) { my $i = $i; print $i }

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In all three, $i disapears after the closing brace. So, why does the middle one fail with closures? 
Paris Sinclair    |    4a75737420416e6f74686572
pariss@efn.org    |    205065726c204861636b6572
http://sinclairinternetwork.com

In reply to RE: Re: for loops by Aighearach
in thread for loops, closures by Aighearach

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