It would output "\`\n" if it acted upon the ordinal value.

But since ++ doesn't act on ordinal values, why should --? Furthermore, what should: 

    my $a = "a";
    $a --;
    print $a;

[download]

print on an EBCDIC platform?

Abigail

In reply to Re: $a++ allowed by $a-- is not ! why? by Abigail-II
in thread $a++ allowed by $a-- is not ! why? by abhishes

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