Monks,

I have inherited some code that does what would appear to be a simple binning operation. However, I have discovered an error in the binning but for the life of me don't see what's wrong with the code.

Given a set of data between 0.9 and 1, the code should place it in 12 different bins.
Bin 0 is < 0.9,
Bin 1 >= 0.9 && < 0.91,
Bin 2 >= 0.91 && < 0.92,
etc..
Bin 11 >= 1.0

When run, some values get shifted down, others are placed in appropriate bins. So far, I am concerned with the < operator because it shows for example, that 0.99 is < 0.99. I hope there is a stupid mistake that I am just missing; I'd appreciate any assistance. Whether the binning algorithm is efficient or not, I'm not currently concerned with, first and foremost is that it work.

Here's the code...

#!/usr/bin/perl use strict; my %final_data = ( '1' => 1.000, '2' => 0.990, '3' => 0.980, '4' => 0.970, '5' => 0.960, '6' => 0.950, '7' => 0.940, '8' => 0.930, '9' => 0.920, '10' => 0.910, '11' => 0.900, '12' => 0.890, ); my $min = 0.90; my $max = 1.00; my $low; my $high; my $incr = 0.01; DATA_ITEM: for my $key ( sort { $a <=> $b } keys %final_data ) { $low = $min; $high = $min + $incr; for my $bin ( 1 .. 10 ) { if( $final_data{$key} < $min ) { warn "$final_data{$key} fell in bin 0 ( $final_data{$key} < $min +)\n"; $low = $high; $high += $incr; next DATA_ITEM; } elsif( $final_data{$key} >= $max ) { warn "$final_data{$key} fell in bin 11 ( $final_data{$key} >= $ma +x )\n"; $low = $high; $high += $incr; next DATA_ITEM; } elsif( ($final_data{$key} >= $low) && ($final_data{$key} < $high +) ) { warn "$final_data{$key} fell in bin $bin ( $final_data{$key} >= $ +low && $final_data{$key} < $high )\n"; $low = $high; $high += $incr; next DATA_ITEM; } $low = $high; $high += $incr; } }

Inelukii

In reply to When < isn't less than by inelukii

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